a^2-4a+3=-10

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Solution for a^2-4a+3=-10 equation:


Simplifying
a2 + -4a + 3 = -10

Reorder the terms:
3 + -4a + a2 = -10

Solving
3 + -4a + a2 = -10

Solving for variable 'a'.

Reorder the terms:
3 + 10 + -4a + a2 = -10 + 10

Combine like terms: 3 + 10 = 13
13 + -4a + a2 = -10 + 10

Combine like terms: -10 + 10 = 0
13 + -4a + a2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-13' to each side of the equation.
13 + -4a + -13 + a2 = 0 + -13

Reorder the terms:
13 + -13 + -4a + a2 = 0 + -13

Combine like terms: 13 + -13 = 0
0 + -4a + a2 = 0 + -13
-4a + a2 = 0 + -13

Combine like terms: 0 + -13 = -13
-4a + a2 = -13

The a term is -4a.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4a + 4 + a2 = -13 + 4

Reorder the terms:
4 + -4a + a2 = -13 + 4

Combine like terms: -13 + 4 = -9
4 + -4a + a2 = -9

Factor a perfect square on the left side:
(a + -2)(a + -2) = -9

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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